Jika kamu sedang melihat jawaban dari pertanyaan omg pls help me guys ente berada di tempat yang tepat. Kami punya 1 jawaban mengenai omg pls help me guys. Silakan pelajari jawaban lebih lanjut disini:
Omg Pls Help Me Guys
Jawaban: #1:Diketahui:
[tex]m \; zat \; X = 17,1 \; gr[/tex]
[tex]m \; air = 200 \; gr[/tex]
[tex]T_b \; larutan = 100,13^\circC[/tex]
[tex]K_b \; air = 0,52^\circC/m[/tex]
Ditanya:
[tex]M_r \; zat \; X = \; ?[/tex]
Jawab:
Ingat kembali rumus-rumus kenaikan titik didih (ΔTb):
[tex]\Delta T_b = T_b \; larutan - T_b \; air[/tex]
[tex]\Delta T_b = molal \cdot K_b \; \; \; \; \; \; \; \; \textit\textbf(untuk larutan nonelektrolit)[/tex]
[tex]\Delta T_b = molal \cdot K_b \cdot i \; \; \; \; \textit\textbf(untuk larutan elektrolit)[/tex]
Keterangan:
[tex]\Delta T_b[/tex] = kenaikan titik didih (°C)
[tex]T_b \; larutan[/tex] = titik didih larutan (°C)
[tex]T_b \; air[/tex] = titik didih air (100°C)
[tex]molal[/tex] = molalitas (m)
[tex]K_b[/tex] = tetapan kenaikan titik didih molal (°C/m)
[tex]i[/tex] = faktor Van't Hoff
Pertama-tama, kita cari dulu kenaikan titik didih larutannya (ΔTb):
[tex]\Delta T_b = T_b \; larutan - T_b \; air[/tex]
[tex]\Delta T_b = 100,13 - 100[/tex]
[tex]\Delta T_b =0,13^\circC[/tex]
Kemudian, kita cari molal dari larutan.
Karena zat X dinyatakan larutan nonelektrolit (pada soal), maka gunakan rumus:
[tex]\Delta T_b = molal \cdot K_b[/tex]
[tex]0,13 = molal \cdot 0,52[/tex]
[tex]molal = \frac0,130,52[/tex]
[tex]molal = 0,25 \; m[/tex]
Selanjutnya, kita cari Mr zat X menggunakan rumus molal:
[tex]molal=\fracm \; terlarutM_r \; terlarut \cdot \frac1000m \; pelarut[/tex]
Keterangan:
[tex]molal[/tex] = molalitas (m)
[tex]m \; terlarut[/tex] = massa zat terlarut (gr)
[tex]M_r \; terlarut[/tex] = massa molekul relatif zat terlarut (gr/mol)
[tex]m \; pelarut[/tex] = massa zat pelarut (gr)
Pada soal, air merupakan zat pelarut, sedangkan X merupakan zat terlarut. Dengan demikian:
[tex]molal=\fracm \; terlarutM_r \; terlarut \cdot \frac1000m \; pelarut[/tex]
[tex]molal=\fracm \; zat \; XM_r \; zat \; X \cdot \frac1000m \; air[/tex]
[tex]0,25=\frac17,1M_r \; zat \; X \cdot \frac1000200[/tex]
[tex]0,25=\frac17,1M_r \; zat \; X \cdot 5[/tex]
[tex]0,25=\frac85,5M_r \; zat \; X[/tex]
[tex]M_r \; zat \; X=\frac85,50,25[/tex]
[tex]M_r \; zat \; X=342 \; gr/mol[/tex]
Jadi, Mr zat X adalah 342 gr/mol.
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